0=-3x^2+126x+5589

Solution for 0=-3x^2+126x+5589 equation:

0=-3x^2+126x+5589

We move all terms to the left:

0-(-3x^2+126x+5589)=0

We add all the numbers together, and all the variables

-(-3x^2+126x+5589)=0

We get rid of parentheses

3x^2-126x-5589=0

a = 3; b = -126; c = -5589;
Δ = b2-4ac
Δ = -1262-4·3·(-5589)
Δ = 82944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{82944}=288$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-288}{2*3}=\frac{-162}{6}
=-27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+288}{2*3}=\frac{414}{6}
=69
$